#!/usr/bin/env python # -*- coding: utf-8 -*- # Copyright © 2012-2017 Zulip, Inc. # # Permission is hereby granted, free of charge, to any person obtaining a copy # of this software and associated documentation files (the "Software"), to deal # in the Software without restriction, including without limitation the rights # to use, copy, modify, merge, publish, distribute, sublicense, and/or sell # copies of the Software, and to permit persons to whom the Software is # furnished to do so, subject to the following conditions: # # The above copyright notice and this permission notice shall be included in # all copies or substantial portions of the Software. # # THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR # IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY, # FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE # AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER # LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, # OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN # THE SOFTWARE. from __future__ import print_function import argparse from six.moves import StringIO as _StringIO from typing import IO import zulip class StringIO(_StringIO): name = '' # https://github.com/python/typeshed/issues/598 usage = """upload-file --user= --api-key= [options] Upload a file, and print the corresponding URI. Example: upload-file --user=cordelia@zulip.com --api-key=a0b1c2d3e4f5a6b7c8d9e0f1a2b3c4d5 --file-path=cat.png You can omit --user and --api-key arguments if you have a properly set up ~/.zuliprc If no --file-path is specified, a placeholder text file will be used instead. """ parser = zulip.add_default_arguments(argparse.ArgumentParser(usage=usage)) parser.add_argument('--file-path') options = parser.parse_args() client = zulip.init_from_options(options) file = None # type: IO if options.file_path: file = open(options.file_path, 'rb') else: file = StringIO('This is a test file.') file.name = 'test.txt' response = client.upload_file(file) try: print('File URI: {}'.format(response['uri'])) except KeyError: print('Error! API response was: {}'.format(response))