cb6ae09bc8
Now, the `Client.do_api_query()` method supports sending files to the API. This has allowed the implementation of a new method, `Client.upload_file(file)`. It simply uploads the file set in the parameter, and returns the API's response (that includes the URI). Despite the fact that `do_api_query()` supports multiple files as parameters, `upload_file()` doesn't, because right now the API isn't capable of managing more than a file in the same request.
67 lines
2.3 KiB
Python
Executable file
67 lines
2.3 KiB
Python
Executable file
#!/usr/bin/env python
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# -*- coding: utf-8 -*-
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# Copyright © 2012-2017 Zulip, Inc.
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#
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# Permission is hereby granted, free of charge, to any person obtaining a copy
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# of this software and associated documentation files (the "Software"), to deal
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# in the Software without restriction, including without limitation the rights
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# to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
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# copies of the Software, and to permit persons to whom the Software is
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# furnished to do so, subject to the following conditions:
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#
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# The above copyright notice and this permission notice shall be included in
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# all copies or substantial portions of the Software.
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#
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# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
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# IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
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# FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
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# AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
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# LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
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# OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
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# THE SOFTWARE.
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from __future__ import print_function
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import importlib
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import optparse
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import sys
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from six.moves import StringIO as _StringIO
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sys.path.insert(0, './api')
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from typing import IO
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import zulip
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class StringIO(_StringIO):
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name = '' # https://github.com/python/typeshed/issues/598
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usage = """upload-file --user=<user's email address> --api-key=<user's api key> [options]
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Upload a file, and print the corresponding URI.
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Example: upload-file --user=cordelia@zulip.com --api-key=a0b1c2d3e4f5a6b7c8d9e0f1a2b3c4d5 --file-path=cat.png
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You can omit --user and --api-key arguments if you have a properly set up ~/.zuliprc
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If no --file-path is specified, a placeholder text file will be used instead.
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"""
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parser = optparse.OptionParser(usage=usage)
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parser.add_option('--file-path')
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parser.add_option_group(zulip.generate_option_group(parser))
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(options, args) = parser.parse_args()
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client = zulip.init_from_options(options)
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file = None # type: IO
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if options.file_path:
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file = open(options.file_path, 'rb')
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else:
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file = StringIO('This is a test file.')
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file.name = 'test.txt'
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response = client.upload_file(file)
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try:
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print('File URI: {}'.format(response['uri']))
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except KeyError:
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print('Error! API response was: {}'.format(response))
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